sql 练习

-- DROP TABLE IF EXISTS `dept`;

-- CREATE TABLE `dept` (

-- `deptno` int PRIMARY KEY ,

-- `dename` VARCHAR(14) ,

-- `loc` VARCHAR(13)

-- );

-- INSERT INTO DEPT VALUES (10,‘ACCOUNTING‘,‘NEW YORK‘);

--

-- INSERT INTO DEPT VALUES (20,‘RESEARCH‘,‘DALLAS‘);

--

-- INSERT INTO DEPT VALUES (30,‘SALES‘,‘CHICAGO‘);

--

-- INSERT INTO DEPT VALUES (40,‘OPERATIONS‘,‘BOSTON‘);

--

--

-- DROP TABLE IF EXISTS emp;

-- CREATE TABLE emp (

-- empno int PRIMARY KEY,

-- ename VARCHAR(10),

-- job VARCHAR(9),

-- mgr INT,

-- hiredare DATE,

-- sal DOUBLE,

-- comm DOUBLE,

-- deptno INT

-- );

-- ALTER TABLE emp ADD CONSTRAINT FOREIGN KEY emp(deptno) REFERENCES dept (deptno);

-- INSERT INTO EMP VALUES(7369,‘SMITH‘,‘CLERK‘,7902,"1980-12-17",800,NULL,20);

--

-- INSERT INTO EMP VALUES(7499,‘ALLEN‘,‘SALESMAN‘,7698,‘1981-02-20‘,1600,300,30);

--

-- INSERT INTO EMP VALUES(7521,‘WARD‘,‘SALESMAN‘,7698,‘1981-02-22‘,1250,500,30);

--

-- INSERT INTO EMP VALUES(7566,‘JONES‘,‘MANAGER‘,7839,‘1981-04-02‘,2975,NULL,20);

--

-- INSERT INTO EMP VALUES(7654,‘MARTIN‘,‘SALESMAN‘,7698,‘1981-09-28‘,1250,1400,30);

--

-- INSERT INTO EMP VALUES(7698,‘BLAKE‘,‘MANAGER‘,7839,‘1981-05-01‘,2850,NULL,30);

--

-- INSERT INTO EMP VALUES(7782,‘CLARK‘,‘MANAGER‘,7839,‘1981-06-09‘,2450,NULL,10);

--

-- INSERT INTO EMP VALUES(7788,‘SCOTT‘,‘ANALYST‘,7566,‘1987-07-03‘,3000,NULL,20);

--

-- INSERT INTO EMP VALUES(7839,‘KING‘,‘PRESIDENT‘,NULL,‘1981-11-17‘,5000,NULL,10);

--

-- INSERT INTO EMP VALUES(7844,‘TURNER‘,‘SALESMAN‘,7698,‘1981-09-08‘,1500,0,30);

--

-- INSERT INTO EMP VALUES(7876,‘ADAMS‘,‘CLERK‘,7788,‘1987-07-13‘,1100,NULL,20);

--

-- INSERT INTO EMP VALUES(7900,‘JAMES‘,‘CLERK‘,7698,‘1981-12-03‘,950,NULL,30);

--

-- INSERT INTO EMP VALUES(7902,‘FORD‘,‘ANALYST‘,7566,‘1981-12-03‘,3000,NULL,20);

--

-- INSERT INTO EMP VALUES(7934,‘MILLER‘,‘CLERK‘,7782,‘1981-01-23‘,1300,NULL,10); -- DROP TABLE IF EXISTS salgrade;

-- CREATE TABLE salgrade (

-- grade INT,

-- losal DOUBLE,

-- hisal DOUBLE

-- );

-- INSERT INTO SALGRADE VALUES (1,700,1200);

--

-- INSERT INTO SALGRADE VALUES (2,1201,1400);

--

-- INSERT INTO SALGRADE VALUES (3,1401,2000);

--

-- INSERT INTO SALGRADE VALUES (4,2001,3000);

--

-- INSERT INTO SALGRADE VALUES (5,3001,9999);

-- 1、查询部门30中员工的详细信息

-- SELECT * from emp WHERE deptno=30;

-- 2、找出从事clerk工作的员工的编号、姓名、部门号

-- SELECT empno ,ename,deptno from emp WHERE job=‘CLERK‘;

-- 3、检索出奖金多于基本工资的员工信息

-- SELECT * from emp where comm > sal;

-- 4、检索出奖金多余基本工资60%的员工

-- SELECT * FROM emp where comm >sal*0.6

-- 5、找出10部门的经理,20部门的员工信息

-- SELECT * from emp where deptno=10 AND job=‘manager‘ or deptno=20 AND job=‘clerk‘;

-- 6、找出10部门的经理,20部门的员工信息或既不属于经理也不属于职员,但工资高于2000的员工

-- SELECT * from emp where deptno=10 AND job=‘manager‘ or deptno=20 AND job=‘clerk‘ or job not in(‘manager‘,‘clerk‘) AND sal>2000;

-- 7、找出获得奖金的员工

-- SELECT * from emp WHERE comm >0

-- 8、找出奖金少于100或没有获得奖金的人

-- SELECT * from emp WHERE comm<100 or comm is null

-- 9、找出姓名以ABS开头的员工

-- SELECT * from emp WHERE ename like ‘a%‘ or ename like ‘b%‘ or ename like ‘s%‘

-- 10、找到名字长度为6个字符的员工

-- SELECT * from emp WHERE length(ename)=6

-- 11、找出名字中不包含r的员工

-- SELECT * from emp WHERE ename not like ‘%r%‘

-- 12、返回员工的信息,并按照姓名进行排序

-- SELECT * from emp  ORDER BY ename asc

-- 13、按照工作降序、工资升序排列

-- SELECT * from emp ORDER BY job desc , sal asc

-- 14、计算员工的日薪资

-- SELECT ename,sal/30 as ‘avg(sal)‘ from emp

-- 15、找出姓名中包含a的员工

-- SELECT * from emp WHERE ename LIKE ‘%a%‘

-- 16、返回拥有员工的部门名和部门号

-- SELECT a.ename,a.deptno,b.dename from emp a LEFT JOIN dept b on a.deptno=b.deptno

-- 17、工资水平多于smith的员工信息。

-- SELECT *FROM emp WHERE sal > (SELECT sal from emp WHERE ename=‘smith‘)

-- 18、返回员工和所属经理的姓名。

-- SELECT a.ename,b.ename from emp a LEFT JOIN emp b on a.mgr=b.empno WHERE b.job=‘manager‘

-- 19、返回雇员的雇佣日期早于其经理雇佣日期的员工及其经理姓名。

-- SELECT a.ename,b.ename from emp a  INNER JOIN emp b on a.mgr=b.empno WHERE a.hiredare<b.hiredare

-- 20、返回员工姓名及其所在的部门名称。

-- SELECT a.ename,b.dename FROM emp a LEFT JOIN dept b on a.deptno=b.deptno

-- 21、返回从事clerk工作的员工姓名和所在部门名称。

-- SELECT a.ename,b.dename from emp a LEFT JOIN dept b on a.deptno=b.deptno WHERE a.job=‘clerk‘

-- 22、返回部门号及其本部门的最低工资。

-- SELECT deptno,min(sal) from emp  GROUP BY deptno

-- 23、返回销售部(sales)所有员工的姓名。

-- SELECT a.ename from  emp a LEFT JOIN dept b on a.deptno=b.deptno WHERE b.dename=‘sales‘

-- 24、返回工资水平多于平均工资的员工。

-- SELECT * from emp WHERE sal> (SELECT avg(sal) FROM emp)

-- 25、返回与SCOTT从事相同工作的员工。

-- SELECT * from emp WHERE job in(  SELECT a.job from emp a WHERE a.ename=‘scott‘)

-- 26、返回与30部门员工工资水平相同的员工姓名与工资。

-- SELECT * from emp WHERE sal in(SELECT sal from emp WHERE deptno=30)

-- 27、返回部门号、部门名、部门所在位置及其每个部门的员工总数。   

-- SELECT a.deptno,b.dename,b.loc,count(*) as cc from emp a LEFT JOIN dept b on a.deptno=b.deptno GROUP BY a.deptno

-- 26、返回员工的姓名、所在部门名及其工资。

-- SELECT a.ename,b.dename,a.sal from emp a ,dept b WHERE a.deptno=b.deptno

-- 27、返回员工的详细信息。(包括部门名)

-- SELECT * from emp,dept,salgrade WHERE emp.deptno=dept.deptno AND emp.sal BETWEEN losal AND hisal

-- 28、返回员工工作及其从事此工作的最低工资。

-- SELECT * ,min(sal) from emp GROUP BY job

-- 29、返回不同部门经理的最低工资。

-- SELECT * ,min(sal) FROM emp WHERE job=‘manager‘  GROUP BY deptno

-- 30、计算出员工的年薪,并且以年薪排序

-- SELECT *,sal*12 as nianxin from emp ORDER BY nianxin  asc

-- 31、返回工资处于第四级别的员工的姓名。

-- SELECT * from emp a ,salgrade b WHERE a.sal BETWEEN losal AND hisal  AND grade=4

-- 32、返回工资为二等级的职员名字、部门所在地、和二等级的最低工资和最高工资

-- SELECT * FROM emp a ,salgrade b,dept c WHERE sal BETWEEN losal AND hisal AND grade=2  AND a.deptno=c.deptno

-- 33、返回工资为二等级的职员名字、部门所在地、二等级员工工资的最低工资和最高工资

-- SELECT ename,loc ,(SELECT min(sal) from emp,salgrade WHERE sal BETWEEN losal and hisal AND grade=2),(SELECT max(sal) from emp,salgrade WHERE sal BETWEEN losal and hisal AND grade=2)

-- from  emp ,dept ,salgrade WHERE sal BETWEEN  losal AND hisal AND grade=2 AND emp.deptno=dept.deptno

-- 34、工资等级多于smith的员工信息。

--   SELECT * from emp WHERE sal>(SELECT hisal FROM emp ,salgrade WHERE ename=‘smith‘ AND sal BETWEEN losal AND hisal) -- select * from emp,salgrade where sal between losal and hisal and grade >(select grade from emp,salgrade where sal between losal

--  and hisal and ename = ‘smith‘);

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