Employee 表包含所有员工信息，每个员工有其对应的 Id, salary 和 department Id 。

+----+-------+--------+--------------+| Id | Name | Salary | DepartmentId |+----+-------+--------+--------------+| 1 | Joe | 70000 | 1 || 2 | Henry | 80000 | 2 || 3 | Sam | 60000 | 2 || 4 | Max | 90000 | 1 || 5 | Janet | 69000 | 1 || 6 | Randy | 85000 | 1 |+----+-------+--------+--------------+

Department 表包含公司所有部门的信息。

+----+----------+| Id | Name |+----+----------+| 1 | IT || 2 | Sales |+----+----------+

编写一个 SQL 查询，找出每个部门工资前三高的员工。例如，根据上述给定的表格，查询结果应返回：

+------------+----------+--------+| Department | Employee | Salary |+------------+----------+--------+| IT | Max | 90000 || IT | Randy | 85000 || IT | Joe | 70000 || Sales | Henry | 80000 || Sales | Sam | 60000 |+------------+----------+--------+

# Write your MySQL query statement belowselect d.name as Department,e.name as Employee,e.salary as Salary from employee as e inner join department as d on e.DepartmentId=d.id where (select count( distinct salary) from employee where salary>e.salary and departmentid=e.DepartmentId )<3 order by e.departmentid,Salary desc