SQL练习题 注:查询列表不建议用 “*” 1.列出至少有一个雇员的所有部门; a.
select * from dept where deptno in(select distinct deptno from emp);
b. (oracle11gCBO 新特性 in(多个值)会智能过滤掉重复字段,通过执行计划验证);
select * from dept where deptno in (select deptno from emp group by deptno having count(deptno)>=1);
c.
select * from dept a where exists (select null from emp b where a.deptno=b.deptno);
2.列出薪金比smith多的所有雇员
select ename from emp where sal>(select sal from emp where ename=‘SMITH‘);
3.列出雇员的姓名及其直接上级姓名(注:列出执行计划原由于显示结果不同,结果显示第二个执行计划要优秀一点,第一个执行计划走了全表扫描也符合常理,第二个走的唯一索引,索引>堆表;测试表较小没有参考价值仅得出结果不同,有利于以后做查询优化) a.
select e.ename,p.ename from emp e,emp p where p.empno(+)=e.mgr;select p.ename,e.ename from emp p left join emp e on e.empno=p.mgr;
执行计划:
Execution Plan----------------------------------------------------------Plan hash value: 2341341676 ---------------------------------------------------------------------------| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |---------------------------------------------------------------------------| 0 | SELECT STATEMENT | | 14 | 280 | 7 (15)| 00:00:01 ||* 1 | HASH JOIN OUTER | | 14 | 280 | 7 (15)| 00:00:01 || 2 | TABLE ACCESS FULL| EMP | 14 | 140 | 3 (0)| 00:00:01 || 3 | TABLE ACCESS FULL| EMP | 14 | 140 | 3 (0)| 00:00:01 |--------------------------------------------------------------------------- Predicate Information (identified by operation id):--------------------------------------------------- 1 - access("E"."EMPNO"(+)="P"."MGR") Statistics---------------------------------------------------------- 1 recursive calls 0 db block gets 15 consistent gets 0 physical reads 0 redo size 823 bytes sent via SQL*Net to client 523 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 14 rows processed
b.
select e.ename,(select ename from emp p where p.empno=e.mgr)as BoosName from emp e;
执行计划:
Execution Plan----------------------------------------------------------Plan hash value: 4000517069 -------------------------------------------------------------------------------------- | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | -------------------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 14 | 140 | 3 (0)| 00:00:01 | | 1 | TABLE ACCESS BY INDEX ROWID| EMP | 1 | 10 | 1 (0)| 00:00:01 | |* 2 | INDEX UNIQUE SCAN | PK_EMP | 1 | | 0 (0)| 00:00:01 | | 3 | TABLE ACCESS FULL | EMP | 14 | 140 | 3 (0)| 00:00:01 | -------------------------------------------------------------------------------------- Predicate Information (identified by operation id):--------------------------------------------------- 2 - access("P"."EMPNO"=:B1) Statistics---------------------------------------------------------- 1 recursive calls 0 db block gets 17 consistent gets 0 physical reads 0 redo size 849 bytes sent via SQL*Net to client 523 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 14 rows processed
4.列出入职日期早于其直接上级的所有雇员
a.select p.ename from emp e,emp p where e.empno=p.mgr and p.hiredate<e.hiredate;
b.
select e.ename from emp e where e.hiredate<(select hiredate from emp p where p.empno=e.mgr);
5、列出部门名称和这些部门的雇员,同时列出那些没有雇员的部门 a.
select a.dname,b.ename from dept a,emp b where a.deptno=b.deptno(+);
b.
select a.dname,b.ename from dept a left join emp b on a.deptno=b.deptno
6、列出所有“CLERK”(办事员)的姓名及其部门名称
select b.ename,a.dname from dept a,emp b where a.deptno=b.deptno and b.job=‘CLERK‘;
7、列出各种工作类别的最低薪金,显示最低薪金大于1500的记录
select min(sal)as minsal,job from emp group by job having min(sal)>1500;
--8、列出从事“SALESMAN”(销售)工作的雇员的姓名,假定不知道销售部的部门编号
select ename from emp where deptno=(select deptno from dept where dname=‘SALES‘);
9、列出薪金高于公司平均水平的所有雇员
select ename from emp where sal>(select avg(sal) from emp);
10、列出与“SCOTT”从事相同工作的所有雇员
select ename from emp where job=(select job from emp where ename=‘SCOTT‘);
11、列出某些雇员的姓名和薪金,条件是他们的薪金等于部门30中任何一个雇员的薪金
select ename,sal from emp where sal in (select sal from emp where deptno=30);
12、列出某些雇员的姓名和薪金,条件是他们的薪金高于部门30中所有雇员的薪金
select ename,sal from emp where sal > (select max(sal) from emp where deptno=30);
13、列出每个部门的信息以及该部门中雇员的数量
select a.deptno,a.dname,a.loc,b.ss from dept a,(select deptno,count(ename) ss from emp group by deptno) bwhere a.deptno=b.deptno;
14、列出所有雇员的雇员名称、部门名称和薪金
select a.ename,b.dname,a.sal from emp a,dept b where a.deptno=b.deptno(+);
15、列出从事同一种工作但属于不同部门的雇员的不同组合
select a.ename,b.ename,a.job,b.job,a.deptno,b.deptno from emp a,emp bwhere a.job=b.job and a.deptno<>b.deptno;
16、列出分配有雇员数量的所有部门的详细信息,即使是分配有0个雇员 a.
select a.deptno,a.dname,a.loc,nvl(b.ss,0) from dept a,(select deptno,count(ename) ss from emp group by deptno) b where a.deptno=b.deptno(+);
b.
select a.deptno,dname,loc,count(empno) ss from dept a,emp b where a.deptno=b.deptno(+)group by a.deptno,a.dname,a.loc;
17、列出各种类别工作的最低工资
select job,min(sal) as minjobsal from emp group by job;
18、列出各个部门的MANAGER(经理)的最低薪金
select deptno,min(sal) ss from emp where job=‘MANAGER‘ group by deptno;
19、列出按年薪排序的所有雇员的年薪
select ename,(sal*12+nvl(comm,0)) as nianxin from emp order by nianxin;
20、列出薪金水平处于第四位的雇员 a.
select ename,a.tt from (select rownum tt,ename,(sal*12+nvl(comm,0)) as nianxin from emp)a where a.tt=4;
b.
select * from (select ename,sal,rank()over(order by sal desc)as nn from emp) where nn=4;