【小米oj】 找出旋转有序数列的中间值

 1 #define mm(a) memset(a,0,sizeof(a));
 2 #define max(x,y) (x)>(y)?(x):(y)
 3 #define min(x,y) (x)<(y)?(x):(y)
 4 #define Fopen freopen("1.in","r",stdin); freopen("m.out","w",stdout);
 5 #define rep(i,a,b) for(int i=(a);i<=(b);i++)
 6 #define per(i,b,a) for(int i=(b);i>=(a);i--)
 7 #include<bits/stdc++.h>
 8 typedef long long ll;
 9 #define PII pair<ll,ll>
10 using namespace std;
11 const int INF=0x3f3f3f3f;
12 const int MAXN=(int)1e5 + 5;
13 
14 vector<int>v;
15 int main() {
16     string input,temp;
17     while (cin >> input) {
18         istringstream iss(input);
19         v.clear();
20         int max1=0;
21         int min1=INF;
22         while (getline(iss, temp, ‘,‘)) {
23             int x=atoi(temp.c_str());
24             v.push_back(x);
25         }
26         int n=v.size();
27         sort(v.begin(),v.end());
28         printf("%d\n",v[n/2]);
29     }
30     return 0;
31 }