Oracle中使用Table()函数解决For循环中不写成 in (l_idlist)形式的问题

 

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Oracle中使用Table()函数解决For循环中不写成 in (l_idlist)形式的问题

在实际PL/SQL编程中,我们要对动态取出来的一组数据,进行For循环处理,其基本程序逻辑为:

 

1 2 3 4 5 6 7 8 9 10 11 12 create or replace procedure getidlist is    l_idlist varchar2(200); begin    l_idlist:= ‘1,2,3,4‘ ;    for brrs in ( select * from bldroom where bldroomid in (l_idlist))    loop        brrs.structure:= ‘钢混‘ ;    end loop; end ; / show err;

1、编译该程序,可以正常通过;

 

2、执行该程序exec getidlist,系统提示:ORA-01722: invalid number,ORA-06512: at “TT.GETIDLIST”, line 6

 

解决方案:

 

1 CREATE OR REPLACE TYPE type_split IS TABLE OF VARCHAR2 (4000);
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 create or replace function split(p_list varchar2,p_sep varchar2 := ‘,‘ ) return type_split pipelined IS   l_idx pls_integer;   v_list varchar2(50) := p_list;   begin        loop             l_idx := instr(v_list,p_sep);             if l_idx > 0 then                 pipe row(substr(v_list,1,l_idx-1));                 v_list := substr(v_list,l_idx+length(p_sep));             else                  pipe row(v_list);                  exit;             end if;        end loop;        return ;   end split;

此时修改getidlist代码如下:

 

 

1 2 3 4 5 6 7 8 9 10 11 12 create or replace procedure getidlist is    l_idlist varchar2(200); begin    l_idlist:= ‘1,2,3,4‘ ;    for brrs in ( select * from bldroom where bldroomid in ( select column_value from table (split(l_idlist, ‘,‘ ))))    loop        brrs.structure:= ‘钢混‘ ;    end loop; end ; / show err;

 

执行:exec getidlist;

提示错误:ORA-22905: cannot access rows from a non-nested table item

 

再次修改getidlist代码如下:

 

1 2 3 4 5 6 7 8 9 10 11 12 13 14 create or replace procedure getidlist is    brRow    bldroom%rowtype;    l_idlist varchar2(200); begin    l_idlist:= ‘1,2,3,4‘ ;    for idrs in ( select column_value from table (split(l_idlist, ‘,‘ )))    loop        select * into brRow from bldroom where bldroomid=idrs.column_value;        brRow.structure:= ‘ssss‘ ;    end loop; end ; / show err;

 

 

OK,搞定。

 

附:PL/SQL表—table()函数用法

摘录

 

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 /* 利用table()函数,我们可以将PL/SQL返回的结果集代替table。 oracle内存表在查询和报表的时候用的比较多,它的速度相对物理表要快几十倍。 */ /* simple example: 1、table()结合数组: */   create or replace type t_test as object( id integer , rq date , mc varchar2(60) );   create or replace type t_test_table as table of t_test;   create or replace function f_test_array(n in number default null ) return t_test_table as v_test t_test_table := t_test_table(); begin for i in 1 .. nvl(n,100) loop v_test.extend(); v_test(v_test. count ) := t_test(i,sysdate, ‘mc‘ ||i); end loop; return v_test; end f_test_array; /   select * from table (f_test_array(10));   select * from the( select f_test_array(10) from dual);   /* 2、table()结合PIPELINED函数: */   create or replace function f_test_pipe(n in number default null ) return t_test_table PIPELINED as v_test t_test_table := t_test_table(); begin for i in 1 .. nvl(n,100) loop pipe row(t_test(i,sysdate, ‘mc‘ ||i)); end loop; return ; end f_test_pipe; /   select * from table (f_test_pipe(20));   select * from the( select f_test_pipe(20) from dual);   /* 3、table()结合系统包: */   create table test (id varchar2(20)); insert into test values ( ‘1‘ ); commit ; explain plan for select * from test; select * from table (dbms_xplan.display);

 

关于错误:ORA-22905: cannot access rows from a non-nested table item 的解决方案,不知各位大侠有没有更好的解决方案?请指教。